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Question: What is the percent of the unprotonated form of ammonia (Kb NH3 = 1.74 x 10-5) in a solution at pH 8.68? What is the percent of the unprotonated form of ammonia ( Kb NH 3 = 1 . 7 4 x 1 0 - 5 ) in a solution at pH

calculate the pH of the following solutions: 1) 0.40 M NH4ClO4 Kb(NH3)=1.8x10-5 2) 0.45 M NaOCl Ka(HOCl)=3.5x10-8 Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

(Given) Kb for NH3 is 1.8 × 10−5 Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

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kb for nh3|Solved = 8. Use the Henderson

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